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15=5t-4.9t^2
We move all terms to the left:
15-(5t-4.9t^2)=0
We get rid of parentheses
4.9t^2-5t+15=0
a = 4.9; b = -5; c = +15;
Δ = b2-4ac
Δ = -52-4·4.9·15
Δ = -269
Delta is less than zero, so there is no solution for the equation
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